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Analysis Assumptions
This section lists analysis assumptions used. In general the model will be solved using computational fluid dynamics (CFD) for incompressible fluids, which is not time-dependent but with gravitational effects included.
- A 1 hp pump is used to generate a flow rate of 50 gpm.
- A typical two return nozzle pool is considered.
- Water flow is evenly distributed between both pool return nozzles.
- The standard water return and the advanced
Circulator water jet both have the same nozzle dimensions.
The standard water return is fixed in place.
The advanced Circulator water jet rotates 360 degrees at a constant angular velocity of 0.5 rad/sec.
Analysis Approach
This section lists the analysis approach taken. A math simulation of a water-filled pool with one water return was modeled. The analysis approach is to first calculate the effectiveness of a standard pool water return by measuring the amount of pool wall surface it can effectively wet. We will then compare this value to the calculated pool wall area that the advanced Circulator water jet can wet.
The standard pool water return was assumed to be pointed down towards the bottom of the pool. In this way, gravity effects are minimized. Then an iso-surface plot of the water velocity equal to 0.2 m/s was generated. It was felt that water velocity below this value would not result in effective wetting of
the pool wall.
Using standard CAD tools, the wall area wetted by the standard pool return is now calculated. The length and width of the wetted wall area are shown in figures 1 and 2. A measured length of 93.8" by a width of 25.9" gives us 8.44 square feet of wetted area for a standard pool return if we assume a triangle dispersion pattern for the water.
The advanced Circulator water jet will inscribe an arc with a radius of 93.8 inches. If we consider a reduced area of a circle to account for the half of the circle where the advanced Circulator water jet is point up, we can conservatively calculate the wetted area for the advanced Circulator water jet as:
Wetted area (Scrubbed Area) = π r2/1.5 = π 93.82/(1.5 X 144) = 128 square feet.
Figure 3: Length of iso-surface
Figure 4: Width of iso-surface
Analysis Conclusions
By taking the ratio of the two areas we can calculate the effectiveness difference between the standard water return and the advanced Circulator water jet.
Ratio: Advanced Circulator water jet (Surface Area) / Standard
Pool Return (Surface Area) = 128 / 8.44 = 15.17
The advanced Circulator water jet is 1500 % more effective than a standard pool water return in terms of pool wall area wetted by the jet.
This report documents the computational fluid dynamics (CFD) analysis done on an advanced Circulator water jet at U.S. standard temperature and pressure (STP). It also determined the difference in effectiveness between a standard water return and the advanced Circulator water jet invented by Advanced Space-age Systems & Engineering Technologies - ASSET, as being 1500% more effective than a standard pool water return.
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